If the distance between transmitter and receiver doubles, by what factor does the received power change?

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Multiple Choice

If the distance between transmitter and receiver doubles, by what factor does the received power change?

Explanation:
In free-space propagation, received power falls with the square of the distance — the inverse-square law. If the distance doubles, the received power becomes Pr_new = Pr_old / (2^2) = Pr_old / 4. So the power is reduced by a factor of 4 (it becomes one quarter of what it was). This holds assuming the transmitter and receiver antennas stay the same and there are no additional losses or fading.

In free-space propagation, received power falls with the square of the distance — the inverse-square law. If the distance doubles, the received power becomes Pr_new = Pr_old / (2^2) = Pr_old / 4. So the power is reduced by a factor of 4 (it becomes one quarter of what it was). This holds assuming the transmitter and receiver antennas stay the same and there are no additional losses or fading.

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